Additional Mathematics 0606 / Factors and polynomials / 2.82.8: Factor theorem and solving a cubic0606/22/M/J/19 — Question 3 · 6 marksMark as done · Save for later · Show all solutions(i)Given that x−2x - 2x−2 is a factor of ax3−12x2+5x+6ax^{3} - 12x^{2} + 5x + 6ax3−12x2+5x+6, use the factor theorem to show that a=4a = 4a=4.[2]▸ Answer(ii)Showing all your working, factorise 4x3−12x2+5x+64x^{3} - 12x^{2} + 5x + 64x3−12x2+5x+6 and hence solve 4x3−12x2+5x+6=04x^{3} - 12x^{2} + 5x + 6 = 04x3−12x2+5x+6=0.[4]▸ Answer▸ Official mark scheme← 1.7: Intersection of a cubic curve and a line1.6: Constants from remainders and divisibility →