Additional Mathematics 0606 / Logarithmic and exponential functions / 3.323.32: Definite integral as a single logarithm0606/11/O/N/22 — Question 8 · 5 marks · Log laws, ExponentialsMark as done · Save for later · Show all solutionsFind ∫0a(1x+1−1x+2)dx\displaystyle\int_{0}^{a}\left(\frac{1}{x + 1} - \frac{1}{x + 2}\right)\mathrm{d}x∫0a(x+11−x+21)dx, where aaa is a positive constant. Give your answer, as a single logarithm, in terms of aaa.[5]▸ Answer▸ Official mark scheme← 3.3: Single lg and equation with reciprocal logs3.33: Solve for y in terms of p →
