Additional Mathematics 0606 / Logarithmic and exponential functions / 3.333.33: Solve for y in terms of p0606/11/O/N/22 — Question 9 · 5 marks · Change of base, EquationsMark as done · Save for later · Show all solutionsSolve the equation 2logpy+10logyp−9=02\log_{p} y + 10\log_{y} p - 9 = 02logpy+10logyp−9=0, where ppp is a positive constant, giving yyy in terms of ppp.[5]▸ Answer▸ Official mark scheme← 3.32: Definite integral as a single logarithm3.34: Definite integral equal to ln 5 →
