3.47: Log equation and exponential equation

0606/11/O/N/25 — Question 3 · 9 marks · Log laws, Exponentials, Equations

(a)
Solve the equation log2x4=5logx2\log_{2} x - 4 = 5\log_{x} 2.
[5]
(b)
Solve the equation 25e2x=e3x7e2x25e^{2x} = e^{3x} - 7e^{2x}.
[4]