Additional Mathematics 0606 / Logarithmic and exponential functions / 3.483.48: Single lg and reciprocal-base log equation0606/12/O/N/25 — Question 5 · 7 marks · Log laws, Change of base, EquationsMark as done · Save for later · Show all solutions(a)Write 5lga−4lgb−35\lg a - 4\lg b - 35lga−4lgb−3 as a single base 101010 logarithm.[3]▸ Answer(b)Solve the equation log5(x+1)−log(x+1)5=0\log_{5}(x + 1) - \log_{(x + 1)} 5 = 0log5(x+1)−log(x+1)5=0.[4]▸ Answer▸ Official mark scheme← 3.47: Log equation and exponential equation3.49: Sketch y = 5 ln(4x + 3) →
