Additional Mathematics 0606 / Series / 3.833.83: Descending expansion of (2x−14x2)n\left(2x - \dfrac{1}{4x^{2}}\right)^{n}(2x−4x21)n0606/13/O/N/23 — Question 8 · 6 marks · BinomialMark as done · Save for later · Show all solutionsThe first three terms, in descending powers of xxx, in the expansion of (2x−14x2)n\left(2x - \dfrac{1}{4x^{2}}\right)^{n}(2x−4x21)n can be written in the form 256xc+ax5+bx2256x^{c} + ax^{5} + bx^{2}256xc+ax5+bx2, where nnn, aaa, bbb and ccc are integers. Find the values of nnn, aaa, bbb and ccc.[6]▸ Answer▸ Official mark scheme← 3.51: Trig AP and cosec GP3.84: Product (2+ax)5(1+bx)(2 + ax)^{5}(1 + bx)(2+ax)5(1+bx): find aaa and bbb →