Additional Mathematics 0606 / Series / 3.843.84: Product (2+ax)5(1+bx)(2 + ax)^{5}(1 + bx)(2+ax)5(1+bx): find aaa and bbb0606/21/O/N/23 — Question 4 · 7 marks · BinomialMark as done · Save for later · Show all solutionsIn this question aaa and bbb are integers. Three terms in the expansion of (2+ax)5(1+bx)(2 + ax)^{5}(1 + bx)(2+ax)5(1+bx) are 32+112x−240x232 + 112x - 240x^{2}32+112x−240x2. Find the values of aaa and bbb.[7]▸ Answer▸ Official mark scheme← 3.83: Descending expansion of (2x−14x2)n\left(2x - \dfrac{1}{4x^{2}}\right)^{n}(2x−4x21)n3.52: Derivative of xsin 2xx\mathrm{sin}\,2xxsin2x; AP of twelve terms →
