Additional Mathematics 0606 / Trigonometry / 1.121.12: Period and sketch of a tangent graph0606/12/M/J/18 — Question 1 · 4 marksMark as done · Save for later · Show all solutionsIt is given that y=1+tan3xy = 1 + \tan 3xy=1+tan3x.(i)State the period of yyy.[1]▸ Answer(ii)On the axes below, sketch the graph of y=1+tan3xy = 1 + \tan 3xy=1+tan3x for 0°≤x≤180°0^{\degree} \le x \le 180^{\degree}0°≤x≤180°.[3]▸ Answer▸ Official mark scheme← 1.3: Sine curve: constants and sketch1.13: Quadratic in sin and tan double-angle equation →
