Additional Mathematics 0606 / Trigonometry / 1.131.13: Quadratic in sin and tan double-angle equation0606/12/M/J/18 — Question 8 · 8 marksMark as done · Save for later · Show all solutions(a)Solve 3cos2θ+4sinθ=43\cos^{2}\theta + 4\sin\theta = 43cos2θ+4sinθ=4 for 0°≤θ≤180°0^{\degree} \le \theta \le 180^{\degree}0°≤θ≤180°.[4]▸ Answer(b)Solve sin2ϕ=3cos2ϕ\sin 2\phi = \sqrt{3}\cos 2\phisin2ϕ=3cos2ϕ for −π2≤ϕ≤π2-\tfrac{\pi}{2} \le \phi \le \tfrac{\pi}{2}−2π≤ϕ≤2π radians.[4]▸ Answer▸ Official mark scheme← 1.12: Period and sketch of a tangent graph1.14: Cosine rule with surd lengths →
