Additional Mathematics 0606 / Trigonometry / 2.312.31: Cosecant–cotangent over 1 − cos0606/23/O/N/19 — Question 2 · 5 marksMark as done · Save for later · Show all solutions(i)Show that cscx−cotx1−cosx=cscx\dfrac{\csc x - \cot x}{1 - \cos x} = \csc x1−cosxcscx−cotx=cscx.[3]▸ Answer(ii)Hence solve cscx−cotx1−cosx=2\dfrac{\csc x - \cot x}{1 - \cos x} = 21−cosxcscx−cotx=2 for 0°<x<180°0^{\degree} < x < 180^{\degree}0°<x<180°.[2]▸ Answer▸ Official mark scheme← 2.20: Tan–sec sum identity and sine equation2.32: Cotangent phase shift and mixed equation →
