Additional Mathematics 0606 / Trigonometry / 2.322.32: Cotangent phase shift and mixed equation0606/23/O/N/19 — Question 5 · 10 marksMark as done · Save for later · Show all solutions(a)Solve 3cot2(y−π4)=13\cot^{2}\left(y - \tfrac{\pi}{4}\right) = 13cot2(y−4π)=1 for 0<y<π0 < y < \pi0<y<π radians.[4]▸ Answer(b)Solve 7cotz+tanz=7cscz7\cot z + \tan z = 7\csc z7cotz+tanz=7cscz for 0°≤z≤360°0^{\degree} \le z \le 360^{\degree}0°≤z≤360°.[6]▸ Answer▸ Official mark scheme← 2.31: Cosecant–cotangent over 1 − cos2.33: Exact tan and hypotenuse with surds →
