Target Mathematics

3.8: Normal to sine curve and triangle OAB

0606/22/F/M/23 — Question 11 · 9 marks

The normal to the curve y=sin(4xπ)y = \mathrm{sin}(4x - \pi) at the point A(a,0)A(a, 0), where π2<a<π\dfrac{\pi}{2} < a < \pi, meets the yy-axis at the point BB. Find the exact area of triangle OABOAB, where OO is the origin.
[9]