Additional Mathematics 0606 / Trigonometry / 3.713.71: Modulus graphs and inequality0606/11/O/N/22 — Question 1 · 6 marksMark as done · Save for later · Show all solutions(a)On the axes, sketch the graphs of y=∣x+2∣y = |x+2|y=∣x+2∣ and y=5−3∣x∣y = 5-3|x|y=5−3∣x∣ for −2⩽x⩽8-2 \leqslant x \leqslant 8−2⩽x⩽8. State the coordinates of any points where the graphs meet the axes.[4]▸ Answer(b)Hence solve ∣x+2∣⩾5−3∣x∣|x+2| \geqslant 5-3|x|∣x+2∣⩾5−3∣x∣.[2]▸ Answer▸ Official mark scheme← 3.8: Normal to sine curve and triangle OAB3.72: Vectors in a triangle →
