Additional Mathematics 0606 / Trigonometry / 3.1123.112: Sec/tan quadratic in a double angle0606/23/O/N/25 — Question 7 · 6 marksMark as done · Save for later · Show all solutionsSolve the equation 3 sec2x+tan x−3=03\,\mathrm{sec}^{2} x + \mathrm{tan}\,x - 3 = 03sec2x+tanx−3=0 for 0∘⩽x⩽120∘0^{\circ} \leqslant x \leqslant 120^{\circ}0∘⩽x⩽120∘.[6]▸ Answer▸ Official mark scheme← 3.111: Chord of intersection of line and curve3.53: Modulus equation and sine graph sketch →
