Additional Mathematics 0606 / Trigonometry / 3.533.53: Modulus equation and sine graph sketch0606/11/M/J/25 — Question 5 · 5 marksMark as done · Save for later · Show all solutions(a)Solve the equation (2x−1)2=9(2x - 1)^{2} = 9(2x−1)2=9.[3]▸ Answer(b)On the axes, sketch the graph of y=5 sin x−2y = 5\,\mathrm{sin}\,x - 2y=5sinx−2 for 0∘⩽x⩽360∘0^{\circ} \leqslant x \leqslant 360^{\circ}0∘⩽x⩽360∘.[2]▸ Answer▸ Official mark scheme← 3.112: Sec/tan quadratic in a double angle3.54: Definite integral and reciprocal trig identity →
