Target Mathematics

3.26: Cosec equation and y in terms of x

0606/13/M/J/22 — Question 9 · 8 marks

(a)
Solve cosec(2θπ3)=23\mathrm{cosec}\left(2\theta - \dfrac{\pi}{3}\right) = \dfrac{2}{\sqrt{3}} for 0θπ0 \leqslant \theta \leqslant \pi. Give your solutions in terms of π\pi.
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(b)
Given that cosec2θ=2x1\mathrm{cosec}^{2}\theta = 2x - 1 and tan2θ=y+1\mathrm{tan}^{2}\theta = y + 1, find yy in terms of xx.
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