Additional Mathematics 0606 / Trigonometry / 3.353.35: Area and integration0606/21/M/J/23 — Question 7 · 10 marksMark as done · Save for later · Show all solutions(a)The diagram shows the curve y=6x−x2y=6x-x^{2}y=6x−x2 for 0⩽x⩽50\leqslant x\leqslant 50⩽x⩽5 and the line y=xy=xy=x. Find the area of the shaded region.[4]▸ Answer(b)(i)Find ∫(1(2x−6)3+cos x) dx\displaystyle\int\left(\dfrac{1}{(2x-6)^{3}}+\mathrm{cos}\,x\right)\,\mathrm{d}x∫((2x−6)31+cosx)dx.[3]▸ Answer(b)(ii)Find ∫(x4+1)22x dx\displaystyle\int\dfrac{(x^{4}+1)^{2}}{2x}\,\mathrm{d}x∫2x(x4+1)2dx.[3]▸ Answer▸ Official mark scheme← 3.34: Cosine: sketch, amplitude, period3.36: Sec function range, gf and inverse sketch →