Target Mathematics

3.36: Sec function range, gf and inverse sketch

0606/23/M/J/23 — Question 8 · 14 marks

(a)(i)
The function ff is defined by f(x)=secxf(x) = \mathrm{sec}\,x for 2π3xπ\dfrac{2\pi}{3} \leqslant x \leqslant \pi. Find the range of ff.
[1]
(a)(ii)
Solve f(x)=23f(x) = -\dfrac{2}{\sqrt{3}}.
[3]
(a)(iii)
Given g(x)=3x2g(x) = 3 - x^{2} for all real xx and that gfgf exists, state the domain of gfgf.
[1]
(a)(iv)
Solve gf(x)=1gf(x) = 1.
[5]
(b)
The function hh is defined by h(x)=ln(x4)h(x) = \ln(x - 4) for x>4x > 4. Sketch y=h(x)y = h(x) and y=h1(x)y = h^{-1}(x), showing asymptotes and axis intercepts.
[4]