Additional Mathematics 0606 / Logarithms and Exponents / 1.41.4: Quadratic in log base 3 by substitution0606/11/O/N/16 — Question 3 · 6 marks · Log laws, EquationsMark as done · Save for later · Show all solutionsBy using the substitution y=log3xy = \log_{3} xy=log3x, or otherwise, find the values of xxx for which3(log3x)2+log3x5−log39=0.3(\log_{3} x)^{2} + \log_{3} x^{5} - \log_{3} 9 = 0.3(log3x)2+log3x5−log39=0.[6]▸ Answer← 1.3: Logarithmic equations with bases 3, 9 and 41.5: Single logarithm; hence solve a log equation →
