1.5: Single logarithm; hence solve a log equation

0606/11/O/N/18 — Question 7 · 9 marks · Log laws, Change of base, Equations

(a)
Express 2+3lg⁡x−lg⁡y2 + 3\lg x - \lg y as a single logarithm to base 1010.
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(b)(i)
Solve 6x+7−3x=06x + 7 - \dfrac{3}{x} = 0.
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(b)(ii)
Hence, given that 6log⁡a3+7−3log⁡3a=06\log_{a} 3 + 7 - 3\log_{3} a = 0, find the possible values of aa.
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