1.14: Implicit differentiation and a normal

4PM1/1/November/2020 — Question 8 · 10 marks

Given that
2xy+5y=ex,2xy+5y=\mathrm{e}^x,
(a) show that
dydx=y(2x+3)2x+5.\frac{\mathrm{d}y}{\mathrm{d}x}=\frac{y(2x+3)}{2x+5}.
(5)
(b) Find the value of dydx\displaystyle \frac{\mathrm{d}y}{\mathrm{d}x} when x=0\displaystyle x=0.
(2)
(c) Find an equation of the normal to the curve with equation 2xy+5y=ex\displaystyle 2xy+5y=\mathrm{e}^x at the point where x=0\displaystyle x=0. Give your answer in the form
px+qy+r=0,px+qy+r=0,
where p\displaystyle p, q\displaystyle q and r\displaystyle r are integers.
(3)