Scalar and Vector Quantities

22 questions

1.16: Past-paper question 6

4PM1/1R/June/2025 — Question 6 · 9 marks

Referred to a fixed origin O\displaystyle O, the position vector of the point A\displaystyle A is (9a+12b)\displaystyle (9\mathbf{a}+12\mathbf{b})
and the position vector of the point B\displaystyle B is (2a+pb)\displaystyle (2\mathbf{a} + p\mathbf{b}) where a=b=1\displaystyle |\mathbf{a}| = |\mathbf{b}| = 1
Given that AB=25\displaystyle |AB| = 25
(a) show that the two possible values of p\displaystyle p are 12\displaystyle -12 and 36\displaystyle 36
(4)
For p=12\displaystyle p = -12
(b) find a unit vector parallel to OB\displaystyle \overrightarrow{OB}
Give your answer in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b} in its simplest form.
(2)
Point C\displaystyle C lies on OB\displaystyle OB such that OC:CB=2:3\displaystyle OC : CB = 2 : 3
For p=36\displaystyle p = 36
(c) find CA\displaystyle \overrightarrow{CA}
Give your answer in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b} in its simplest form.
(3)

1.17: Past-paper question 8

4PM1/2/June/2025 — Question 8 · 11 marks

1.17 diagram 1
Figure 2 shows triangle OAB\displaystyle OAB with
OA=3u+vOB=u+2v\overrightarrow{OA} = 3\mathbf{u} + \mathbf{v} \quad \overrightarrow{OB} = -\mathbf{u} + 2\mathbf{v}
(a) Find AB\displaystyle \overrightarrow{AB} as a simplified expression in terms of u\displaystyle \mathbf{u} and v\displaystyle \mathbf{v}
(2)
Point C\displaystyle C is such that AC\displaystyle AC is parallel to OB\displaystyle OB
Given that OC=μv\displaystyle \overrightarrow{OC} = \mu\mathbf{v}
(b) find the value of μ\displaystyle \mu
(4)
The lines OC\displaystyle OC and AB\displaystyle AB intersect at point X\displaystyle X
Point D\displaystyle D lies on OC\displaystyle \overrightarrow{OC} such that
area of triangle BOX\displaystyle BOX : area of triangle BXD=2:3\displaystyle BXD = 2 : 3
Using a vector method,
(c) find BD\displaystyle \overrightarrow{BD} as a simplified expression in terms of u\displaystyle \mathbf{u} and v\displaystyle \mathbf{v}
(5)

1.19: The points , , and are the vertices of a quadrilateral where (a) Show that is a trapezium.

4PM1/2/November/2025 — Question 9 · 16 marks

The points A\displaystyle A, B\displaystyle B, C\displaystyle C and D\displaystyle D are the vertices of a quadrilateral where
AB=2a+4bAC=7a+7bAD=10a+6b\overrightarrow{AB} = 2\mathbf{a} + 4\mathbf{b} \quad \overrightarrow{AC} = 7\mathbf{a} + 7\mathbf{b} \quad \overrightarrow{AD} = 10\mathbf{a} + 6\mathbf{b}
(a) Show that ABCD\displaystyle ABCD is a trapezium.
(4)
Given that a=1\displaystyle |\mathbf{a}| = 1 and b=1\displaystyle |\mathbf{b}| = 1 and that a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b} are perpendicular to each other
(b) find a unit vector parallel to BD\displaystyle \overrightarrow{BD}
(4)
The point Y\displaystyle Y lies on CD\displaystyle CD such that CY:YD=1:2\displaystyle CY : YD = 1 : 2
The lines AC\displaystyle AC and BY\displaystyle BY intersect at the point X\displaystyle X
(c) (i) Use a vector method to find the ratio BX:XY\displaystyle BX : XY
(4)
(ii) Hence find, in its simplest form, the ratio
area of triangle CXY\displaystyle CXY : area of trapezium ABCD\displaystyle ABCD
(4)

1.18: Past-paper question 1

4PM1/2R/June/2025 — Question 1 · 4 marks

The points A\displaystyle A, B\displaystyle B, C\displaystyle C and D\displaystyle D are the vertices of a quadrilateral ABCD\displaystyle ABCD such that
AB=3a+2bAD=2a5bAC=5a3b\overrightarrow{AB} = 3\mathbf{a} + 2\mathbf{b} \qquad \overrightarrow{AD} = 2\mathbf{a} - 5\mathbf{b} \qquad \overrightarrow{AC} = 5\mathbf{a} - 3\mathbf{b}
Show that ABCD\displaystyle ABCD is a parallelogram.
(4)

1.12: Past-paper question 8

4PM1/1R/June/2024 — Question 8 · 10 marks

1.12 diagram 1
Figure 3 shows a trapezium ABCD\displaystyle ABCD
BC=3aAD=5aCD=2b\overrightarrow{BC}=3\mathbf{a} \quad \overrightarrow{AD}=5\mathbf{a} \quad \overrightarrow{CD}=2\mathbf{b}
(a) Find AB\displaystyle \overrightarrow{AB} as a simplified expression in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b}
(1)
The diagonals BD\displaystyle BD and AC\displaystyle AC intersect at point X\displaystyle X where BX=kBD\displaystyle \overrightarrow{BX}=k\overrightarrow{BD}
(b) Using a vector method, find the value of k\displaystyle k
(5)
(c) Find the ratio of the area of triangle CXD\displaystyle CXD : area of the trapezium ABCD\displaystyle ABCD
(4)

1.13: Past-paper question 10

4PM1/2/June/2024 — Question 10 · 11 marks

The points A\displaystyle A, B\displaystyle B, C\displaystyle C and D\displaystyle D are the vertices of a quadrilateral such that
AB=3a+4bAC=7a+9bAD=4a+5b\overrightarrow{AB}=3\mathbf{a}+4\mathbf{b} \quad \overrightarrow{AC}=7\mathbf{a}+9\mathbf{b} \quad \overrightarrow{AD}=4\mathbf{a}+5\mathbf{b}
(a) Show that ABCD\displaystyle ABCD is a parallelogram.
(3)
BC\displaystyle BC is extended to the point E\displaystyle E such that BCE\displaystyle BCE is a straight line.
Point F\displaystyle F lies on CD\displaystyle CD such that CF:FD=1:2\displaystyle CF : FD = 1 : 2
Given that A\displaystyle A, F\displaystyle F and E\displaystyle E are collinear,
(b) find the vector AE\displaystyle \overrightarrow{AE} in the form Xa+Yb\displaystyle X\mathbf{a} + Y\mathbf{b} where X\displaystyle X and Y\displaystyle Y are rational numbers to be found.
(8)

1.15: Past-paper question 8

4PM1/2/November/2024 — Question 8 · 12 marks

1.15 diagram 1
Figure 2 shows triangle AOB\displaystyle AOB
OA=4a+5bOB=8abOD=15a+10bwherea=b=1\overrightarrow{OA} = 4\mathbf{a} + 5\mathbf{b} \quad \overrightarrow{OB} = 8\mathbf{a} - \mathbf{b} \quad \overrightarrow{OD} = 15\mathbf{a} + 10\mathbf{b} \quad \mathrm{where} |\mathbf{a}| = |\mathbf{b}| = 1
(a) (i) Find AB\displaystyle \overrightarrow{AB} in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b}
(ii) Find, in its simplest form, the exact value of AB\displaystyle |\overrightarrow{AB}|
(3)
(b) Find the area of triangle AOB\displaystyle AOB
(4)
The point C\displaystyle C lies on AB\displaystyle AB and OD\displaystyle OD such that O\displaystyle O, C\displaystyle C and D\displaystyle D are collinear.
(c) Use a vector method to find vector OC\displaystyle \overrightarrow{OC} as a simplified expression in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b}
(5)

1.14: Past-paper question 3

4PM1/2R/June/2024 — Question 3 · 6 marks

O,A\displaystyle O, A and B\displaystyle B are fixed points such that
OA=35AB=i+3ajOB=7i+2aj\left| \overrightarrow{OA} \right| = 3\sqrt{5} \quad \overrightarrow{AB} = \mathbf{i} + 3a\mathbf{j} \quad \overrightarrow{OB} = 7\mathbf{i} + 2a\mathbf{j}
Given that a>0\displaystyle a > 0
(a) find the value of a\displaystyle a
(4)
(b) Hence find a unit vector parallel to OA\displaystyle \overrightarrow{OA}
(2)

1.8: Past-paper question 10

4PM1/1/June/2023 — Question 10 · 10 marks

O,A\displaystyle O, A and B\displaystyle B are fixed points such that
OA=(b+1)i+bj\overrightarrow{OA} = (b + 1)\mathbf{i} + b\mathbf{j}
AB=3i\overrightarrow{AB} = 3\mathbf{i}
The unit vector parallel to OB\displaystyle \overrightarrow{OB} is 1734[(3a+2)i+bj]\displaystyle \frac{\sqrt{17}}{34} [(3a + 2)\mathbf{i} + b\mathbf{j}]
Given that a\displaystyle a and b\displaystyle b are constants where a>0\displaystyle a > 0 and b>0\displaystyle b > 0
find the exact value of
(i) a\displaystyle a
(ii) b\displaystyle b
(10)

1.9: In Figure 5, , and is the midpoint of .

4PM1/1R/June/2023 — Question 10 · 11 marks

1.9 diagram 1
In Figure 5, OA=2a\displaystyle \overrightarrow{OA} = 2\mathbf{a}, OB=4b\displaystyle \overrightarrow{OB} = 4\mathbf{b} and M\displaystyle M is the midpoint of OA\displaystyle OA.
The point Y\displaystyle Y lies on AB\displaystyle AB such that AY:YB=3:1\displaystyle AY : YB = 3 : 1
The point X\displaystyle X lies on OB\displaystyle OB produced.
(a) Find as simplified expressions in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b}
(i) AB\displaystyle \overrightarrow{AB}      (ii) MY\displaystyle \overrightarrow{MY}
(3)
The points M\displaystyle M, Y\displaystyle Y and X\displaystyle X are collinear.
(b) Find the ratio OB:OX\displaystyle OB : OX
(5)
(c) Find the ratio of (AreaΔYBX):(AreaΔOAX)\displaystyle (\mathrm{Area} \Delta YBX) : (\mathrm{Area} \Delta OAX)
(3)

1.11: Past-paper question 11

4PM1/2/November/2023 — Question 11 · 9 marks

1.11 diagram 1
Figure 3 shows quadrilateral OABC\displaystyle OABC where
OA=4p+5qOB=3p+qOC=2p4q\overrightarrow{OA} = 4\mathbf{p} + 5\mathbf{q} \quad \overrightarrow{OB} = 3\mathbf{p} + \mathbf{q} \quad \overrightarrow{OC} = 2\mathbf{p} - 4\mathbf{q}
The point M\displaystyle M is the midpoint of OC\displaystyle OC
(a) Find MA\displaystyle \overrightarrow{MA} as a simplified expression in terms of p\displaystyle \mathbf{p} and q\displaystyle \mathbf{q}
(3)
The point N\displaystyle N lies on OB\displaystyle OB such that M,N\displaystyle M, N and A\displaystyle A are collinear.
(b) Find the ratio MN:NA\displaystyle MN : NA
(6)

1.10: Past-paper question 4

4PM1/2R/June/2023 — Question 4 · 6 marks

O,A\displaystyle O, A and B\displaystyle B are fixed points such that
OA=5i+7jAB=ai+16jandOB=529\overrightarrow{OA} = 5\mathbf{i} + 7\mathbf{j} \quad \overrightarrow{AB} = a\mathbf{i} + 16\mathbf{j} \quad \mathrm{and} \quad |\overrightarrow{OB}| = 5\sqrt{29}
(a) Find the possible values of a\displaystyle a
(4)
Given that a>0\displaystyle a > 0
(b) find a unit vector that is parallel to AB\displaystyle \overrightarrow{AB}
(2)

1.1: Vectors and an area ratio

4PM1/1/June/2022 — Question 10 · 14 marks

1.1 diagram 1
Figure 4 shows triangle OAB\displaystyle OAB in which
OA=aandOB=b.\overrightarrow{OA}=\mathbf{a} \qquad \text{and} \qquad \overrightarrow{OB}=\mathbf{b}.
The point P\displaystyle P lies on AB\displaystyle AB such that AP:PB=3:1\displaystyle AP:PB=3:1.
The point M\displaystyle M is the midpoint of OA\displaystyle OA and the point N\displaystyle N is the midpoint of OP\displaystyle OP.
(a) Find, as simplified expressions in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b}, the vector
(i) OP\displaystyle \overrightarrow{OP},
(ii) MN\displaystyle \overrightarrow{MN}.
(4)
The point C\displaystyle C lies on OB\displaystyle OB such that ANC\displaystyle ANC is a straight line.
(b) Using a vector method, find OC\displaystyle \overrightarrow{OC} as a simplified expression in terms of b\displaystyle \mathbf{b}.
(6)
Given that
area of quadrilateral AMNParea of triangle OAB=K,\frac{\text{area of quadrilateral }AMNP}{\text{area of triangle }OAB}=K,
(c) find the exact value of K\displaystyle K.
(4)

1.2: Vector proof in a quadrilateral

4PM1/1R/June/2022 — Question 9 · 10 marks

1.2 diagram 1
Figure 3 shows quadrilateral ABCD\displaystyle ABCD such that
AD=2a+b,BC=13b,BD=4ab.\overrightarrow{AD}=2\mathbf{a}+\mathbf{b}, \qquad \overrightarrow{BC}=\frac{1}{3}\mathbf{b}, \qquad \overrightarrow{BD}=-4\mathbf{a}-\mathbf{b}.
(a) Prove that AB\displaystyle \overrightarrow{AB} is parallel to DC\displaystyle \overrightarrow{DC}.
(4)
The diagonals, AC\displaystyle AC and BD\displaystyle BD, of the quadrilateral intersect at the point Y\displaystyle Y.
(b) Using a vector method, find AY\displaystyle \overrightarrow{AY} as a simplified expression in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b}.
(6)

1.3: Find a vector parallel to AB

4PM1/2/June/2022 — Question 3 · 9 marks

O\displaystyle O, A\displaystyle A and B\displaystyle B are fixed points such that
OA=pi4jOB=i+(2p+1)j\overrightarrow{OA} = p\mathbf{i}-4\mathbf{j} \qquad \overrightarrow{OB} = \mathbf{i}+(2p+1)\mathbf{j}
Given that
2OA=OBandp>0,\sqrt{2}\,\lvert\overrightarrow{OA}\rvert = \lvert\overrightarrow{OB}\rvert \quad \text{and} \quad p>0,
(a) find the value of p\displaystyle p.
(4)
Using this value of p\displaystyle p,
(b) find a unit vector that is parallel to AB\displaystyle \overrightarrow{AB}.
(5)

1.4: Position vectors and a unit vector

4PM1/2R/June/2022 — Question 1 · 5 marks

The position vector of the point A\displaystyle A is 3i2j\displaystyle 3\mathbf{i}-2\mathbf{j}, referred to a fixed origin O\displaystyle O.
The point B\displaystyle B is such that
AB=6i+8j.\overrightarrow{AB}=6\mathbf{i}+8\mathbf{j}.
(a) Find the position vector of B\displaystyle B as a simplified expression in terms of i\displaystyle \mathbf{i} and j\displaystyle \mathbf{j}.
(2)
(b) Find the magnitude of AB\displaystyle \overrightarrow{AB}.
(1)
(c) Find a unit vector, in terms of i\displaystyle \mathbf{i} and j\displaystyle \mathbf{j}, that is parallel to AB\displaystyle \overrightarrow{AB}.
(2)

1.5: Intersecting lines using vectors

4PM1/1/June/2021 — Question 10 · 14 marks

1.5 diagram 1
Figure 1 shows triangle OAB\displaystyle OAB and triangle OCD\displaystyle OCD.
OA=5p,AB=3q,OC=32OB,OD=35OA.\overrightarrow{OA}=5\mathbf{p}, \qquad \overrightarrow{AB}=3\mathbf{q}, \qquad \overrightarrow{OC}=\frac32\overrightarrow{OB}, \qquad \overrightarrow{OD}=\frac35\overrightarrow{OA}.
(a) Find DC\displaystyle \overrightarrow{DC} as a simplified expression in terms of p\displaystyle \mathbf{p} and q\displaystyle \mathbf{q}.
(3)
The line DC\displaystyle DC meets the line AB\displaystyle AB at F\displaystyle F.
(b) Using a vector method, find OF\displaystyle \overrightarrow{OF} as a simplified expression in terms of p\displaystyle \mathbf{p} and q\displaystyle \mathbf{q}.
(7)
The point G\displaystyle G lies on OB\displaystyle OB such that FG\displaystyle FG is parallel to AO\displaystyle AO.
(c) Using a vector method, find OG\displaystyle \overrightarrow{OG} as a simplified expression in terms of p\displaystyle \mathbf{p} and q\displaystyle \mathbf{q}.
(4)

1.6: Vectors, collinearity and an area ratio

4PM1/1/November/2020 — Question 11 · 13 marks

1.6 diagram 1
In Figure 5,
OA=aandOB=b.\overrightarrow{OA}=\mathbf{a} \qquad \text{and} \qquad \overrightarrow{OB}=\mathbf{b}.
The point C\displaystyle C divides OB\displaystyle OB in the ratio 1:3\displaystyle 1:3. The point D\displaystyle D is the midpoint of AC\displaystyle AC.
(a) Find, as a simplified expression in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b},
(i) AC\displaystyle \overrightarrow{AC},
(ii) OD\displaystyle \overrightarrow{OD},
(iii) BD\displaystyle \overrightarrow{BD}.
(5)
The point E\displaystyle E is such that OE=λOA\displaystyle \overrightarrow{OE}=\lambda\overrightarrow{OA}. Given that E\displaystyle E, D\displaystyle D and B\displaystyle B are collinear,
(b) find the value of λ\displaystyle \lambda.
(4)
Given that
area of OACarea of OEB=μ,\frac{\text{area of }\triangle OAC}{\text{area of }\triangle OEB}=\mu,
(c) find the value of μ\displaystyle \mu.
(4)

1.7: Intersecting cevians using vectors

4PM1/1R/November/2020 — Question 11 · 13 marks

1.7 diagram 1
Figure 1 shows a triangle OXY\displaystyle OXY.
OX=2aandOY=3b.\overrightarrow{OX}=2\mathbf{a} \qquad \text{and} \qquad \overrightarrow{OY}=3\mathbf{b}.
A\displaystyle A is the midpoint of OX\displaystyle OX and B\displaystyle B is the point on OY\displaystyle OY such that OB:BY=1:2\displaystyle OB:BY=1:2. The lines XB\displaystyle XB and AY\displaystyle AY intersect at Z\displaystyle Z.
(a) Find AB\displaystyle \overrightarrow{AB} as a simplified expression in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b}.
(1)
(b) Using a vector method, find OZ\displaystyle \overrightarrow{OZ} as a simplified expression in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b}.
(9)
The point M\displaystyle M on XY\displaystyle XY is such that O\displaystyle O, Z\displaystyle Z and M\displaystyle M are collinear.
(c) Find OM\displaystyle \overrightarrow{OM} as a simplified expression in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b}.
(3)

1.20: A, and are fixed points such that

4PM1/1R/June/2019 — Question 7 · 8 marks

O\displaystyle O, A\displaystyle A, B\displaystyle B and C\displaystyle C are fixed points such that
OA=8i6j,OB=15i6j,OC=8i+j.\overrightarrow{OA}=8\mathbf{i}-6\mathbf{j}, \qquad \overrightarrow{OB}=15\mathbf{i}-6\mathbf{j}, \qquad \overrightarrow{OC}=8\mathbf{i}+\mathbf{j}.
(a) Find BC\displaystyle \overrightarrow{BC} as a simplified expression in terms of i\displaystyle \mathbf{i} and j\displaystyle \mathbf{j}.
(2)
(b) Find a unit vector parallel to BC\displaystyle \overrightarrow{BC}.
(2)
The point M\displaystyle M is the midpoint of OA\displaystyle OA and the point N\displaystyle N lies on OB\displaystyle OB such that
ON:NB=1:2.ON:NB=1:2.
(c) Show that the points M\displaystyle M, N\displaystyle N and C\displaystyle C are collinear.
(4)

1.21: Referred to a fixed origin the point A has position vector (4i and the point has

4PM1/2/June/2019 — Question 1 · 4 marks

Referred to a fixed origin O\displaystyle O, the point A\displaystyle A has position vector (4i+3j)\displaystyle (4\mathbf{i}+3\mathbf{j}) and the point B\displaystyle B has position vector (i+7j)\displaystyle (\mathbf{i}+7\mathbf{j}).
(a) Find AB\displaystyle \overrightarrow{AB} as a simplified expression in terms of i\displaystyle \mathbf{i} and j\displaystyle \mathbf{j}.
(2)
(b) Find a unit vector that is parallel to AB\displaystyle \overrightarrow{AB}.
(2)

1.22: Past-paper question 3

4PM1/2/January/2019 — Question 3 · 6 marks

Referred (3i (a) Find, respectively. to as a a fixed simplified origin expression the position in terms vectors of i and of the points P\displaystyle P and Q\displaystyle Q are (5i +6j)\displaystyle + 6j) and
(2)
(b) Find a unit vector parallel to PQ.\displaystyle {\overline{{P Q}}}.
(2)
The Given position that vector of the fixed point R\displaystyle R is (13i +\displaystyle + aj), where a is a constant.
(c) find the value of a.
(2)