Further Pure Mathematics 4PM1 / Differentiation / 1.191.19: Verify a second-order differential equation4PM1/2R/November/2020 — Question 9 · 8 marksMark as done · Save for laterGiven thatx=e−tsin 2t,x=\mathrm{e}^{-t}\mathrm{sin}\,2t,x=e−tsin2t,show thatd2xdt2+2dxdt+5x=0.\frac{\mathrm{d}^2x}{\mathrm{d}t^2}+2\frac{\mathrm{d}x}{\mathrm{d}t}+5x=0.dt2d2x+2dtdx+5x=0.(8)▸ Mark scheme← 1.18: 4PM1/2/November/2020 — Question 11.56: 4PM1/1/June/2019 — Question 6 →