Further Pure Mathematics 4PM1 / Differentiation / 1.201.20: Show that where and are integers to be found4PM1/1/June/2023 — Question 2 · 5 marksMark as done · Save for latery=(sin2x)3+2xy = (\mathrm{sin} 2x) \sqrt{3 + 2x}y=(sin2x)3+2xShow that dydx=sin2x+(A+Bx)cos2x3+2x\displaystyle \frac{\mathrm{d}y}{\mathrm{d}x} = \frac{\mathrm{sin} 2x + (A + Bx) \mathrm{cos} 2x}{\sqrt{3 + 2x}}dxdy=3+2xsin2x+(A+Bx)cos2x where A\displaystyle AA and B\displaystyle BB are integers to be found.(5)▸ Mark scheme← 1.39: 4PM1/2R/June/2024 — Question 51.21: 4PM1/1/June/2023 — Question 4 →