1.26: Figure 3 shows a right triangular prism .

4PM1/2/June/2023 — Question 6 · 6 marks

1.26 diagram 1
Figure 3 shows a right triangular prism ABCDEF\displaystyle ABCDEF. A cross section ABC\displaystyle ABC of the prism is a triangle in which AB=AC=rcm\displaystyle AB = AC = r\mathrm{cm} and CAB=π3\displaystyle \angle CAB = \frac{\pi}{3} radians.
In the prism
AE=BF=CD=5cmED=EF=rcmandDEF=π3radiansAE = BF = CD = 5\mathrm{cm} \quad ED = EF = r\mathrm{cm} \quad \mathrm{and} \quad \angle DEF = \frac{\pi}{3} \mathrm{radians}
(a) Show that the volume of the prism is 534r2cm3\displaystyle \frac{5\sqrt{3}}{4} r^2 \mathrm{cm}^3
(1)
The volume of the prism is increasing in such a way that the size of CAB\displaystyle \angle CAB and the size of DEF\displaystyle \angle DEF remain constant and the length of AE\displaystyle AE, the length of BF\displaystyle BF and the length of CD\displaystyle CD remain constant.
The lengths of AB\displaystyle AB, AC\displaystyle AC, ED\displaystyle ED and EF\displaystyle EF are each increasing at a constant rate of 0.2cm/s\displaystyle 0.2\mathrm{cm}/\mathrm{s}
(b) Find the exact rate of increase, in cm3/s\displaystyle \mathrm{cm}^3/\mathrm{s}, of the volume of the prism when the area of the rectangular face BCDF\displaystyle BCDF is 60cm2\displaystyle 60\mathrm{cm}^2
(5)