Further Pure Mathematics 4PM1 / Differentiation / 1.491.49: (a) Show that Given that where and are integers (b) find the value of and the value of4PM1/2/June/2025 — Question 9 · 8 marksMark as done · Save for latery=e−4tcos2ty = \mathrm{e}^{-4t} \mathrm{cos} 2ty=e−4tcos2t(a) Show that 2e−4tsin2t=−dydt−4y\displaystyle 2\mathrm{e}^{-4t} \mathrm{sin} 2t = -\frac{\mathrm{d}y}{\mathrm{d}t} - 4y2e−4tsin2t=−dtdy−4y(3)Given that d2ydt2+Mdydt+Ny=0\displaystyle \frac{\mathrm{d}^{2}y}{\mathrm{d}t^2} + M \frac{\mathrm{d}y}{\mathrm{d}t} + Ny = 0dt2d2y+Mdtdy+Ny=0 where M\displaystyle MM and N\displaystyle NN are integers(b) find the value of M\displaystyle MM and the value of N\displaystyle NN(5)▸ Mark scheme← 1.48: 4PM1/2/June/2025 — Question 61.54: 4PM1/2/November/2025 — Question 4 →