Further Pure Mathematics 4PM1 / Inequalities and Identities / 1.191.19: Equations and inequalities4PM1/1/June/2016 — Question 1 · 5 marksMark as done · Save for laterf(x)=x3−7x+6f(x)=x^3-7x+6f(x)=x3−7x+6(a) Show that (x−2)(x-2)(x−2) is a factor of f(x)f(x)f(x). (2)(b) Hence, or otherwise, factorise f(x)f(x)f(x) completely. (3)▸ Mark scheme← 1.17: 4PM1/2/June/2017 — Question 11.20: 4PM1/1/January/2016 — Question 2 →
