Further Pure Mathematics 4PM1 / Inequalities and Identities / 1.21.2: Equations and inequalities4PM1/2/June/2024 — Question 1 · 6 marksMark as done · Save for laterf(x)=6x3−13x2+ax−10wherea is a constantf(x) = 6x^3 - 13x^2 + ax - 10 \quad \mathrm{where} a \text{ is a constant}f(x)=6x3−13x2+ax−10wherea is a constantGiven that (3x−2)(3x - 2)(3x−2) is a factor of f(x)f(x)f(x)(a) show that a=21a = 21a=21(2)(b) Hence show algebraically that the curve y=f(x)y = f(x)y=f(x) has only one intersection with the xxx-axis.(4)▸ Mark scheme← 1.5: 4PM1/1/November/2024 — Question 11.6: 4PM1/2/November/2024 — Question 2 →