1.20: Past-paper question 9

4PM1/2/November/2024 — Question 9 · 14 marks

1.20 diagram 1
(a) Using a formula given on page 2, show that
cos2θ=2cos2θ1\mathrm{cos} 2\theta = 2 \mathrm{cos}^2 \theta - 1
(2)
(b) Hence show that
π33π4(2cos2θ1)dθ=a+bc\int_{\frac{\pi}{3}}^{\frac{3\pi}{4}} (2 \mathrm{cos}^2 \theta - 1) \mathrm{d}\theta = -\frac{a + \sqrt{b}}{c}
where a\displaystyle a, b\displaystyle b and c\displaystyle c are integers to be found.
(4)
Figure 3 shows part of the curve C1\displaystyle C_1 with equation y=2cos2θ1\displaystyle y = 2 \mathrm{cos}^2 \theta - 1 and part of the curve C2\displaystyle C_2 with equation y=cosθ\displaystyle y = -\mathrm{cos} \theta
Point B\displaystyle B is the intersection of C1\displaystyle C_1 and C2\displaystyle C_2 as shown in Figure 3
Point A(3π4,0)\displaystyle A \left( \frac{3\pi}{4}, 0 \right) is the intersection of C1\displaystyle C_1 with the θ\displaystyle \theta-axis as shown in Figure 3
Point E(π2,0)\displaystyle E \left( \frac{\pi}{2}, 0 \right) is the intersection of C2\displaystyle C_2 with the θ\displaystyle \theta-axis as shown in Figure 3
The finite region R\displaystyle R, shown shaded in Figure 3, is bounded by the θ\displaystyle \theta-axis, C1\displaystyle C_1 and C2\displaystyle C_2
(c) Use calculus to find, in its simplest form, the exact area of R\displaystyle R
(8)