Further Pure Mathematics 4PM1 / Rectangular Cartesian Coordinates / 1.201.20: Past-paper question 94PM1/1R/June/2025 — Question 9 · 9 marksMark as done · Save for laterGiven that f(x)=(1+x2)4\displaystyle f(x) = (1+x^2)^4f(x)=(1+x2)4(a) show that f′(x)=8x(1+x2)3\displaystyle f'(x) = 8x(1+x^2)^3f′(x)=8x(1+x2)3(2)The curve C\displaystyle CC has equation y=sin3x(1+x2)4\displaystyle y = \frac{\mathrm{sin} 3x}{(1+x^2)^4}y=(1+x2)4sin3xThe point A\displaystyle AA on C\displaystyle CC has x\displaystyle xx coordinate 2π3\displaystyle \frac{2\pi}{3}32π(b) Show that the gradient of the normal to C\displaystyle CC at A\displaystyle AA is−13(1+(2π3)2)4-\frac{1}{3} \left( 1 + \left( \frac{2\pi}{3} \right)^2 \right)^4−31(1+(32π)2)4(7)▸ Mark scheme← 1.24: 4PM1/1/November/2025 — Question 101.21: 4PM1/2/June/2025 — Question 10 →