Further Pure Mathematics 4PM1 / Scalar and Vector Quantities / 1.181.18: Past-paper question 14PM1/2R/June/2025 — Question 1 · 4 marksMark as done · Save for laterThe points A\displaystyle AA, B\displaystyle BB, C\displaystyle CC and D\displaystyle DD are the vertices of a quadrilateral ABCD\displaystyle ABCDABCD such thatAB→=3a+2bAD→=2a−5bAC→=5a−3b\overrightarrow{AB} = 3\mathbf{a} + 2\mathbf{b} \qquad \overrightarrow{AD} = 2\mathbf{a} - 5\mathbf{b} \qquad \overrightarrow{AC} = 5\mathbf{a} - 3\mathbf{b}AB=3a+2bAD=2a−5bAC=5a−3bShow that ABCD\displaystyle ABCDABCD is a parallelogram.(4)▸ Mark scheme← 1.19: 4PM1/2/November/2025 — Question 91.12: 4PM1/1R/June/2024 — Question 8 →