Further Pure Mathematics 4PM1 / Surds and Logarithmic Functions / 1.381.38: Logarithmic Equations and Laws4PM1/1/June/2019 — Question 9 · 12 marksMark as done · Save for later(a) Solve the equation2logp9+3log3p=8.2\log_p 9+3\log_3 p=8.2logp9+3log3p=8.(6)Given thatlog23=log43k,\log_2 3=\log_4 3^k,log23=log43k,(b) find the value of k\displaystyle kk.(2)(c) Show that6xlog4x−3xlog23−5log4x+10log23=log4(x6x−536x−20).6x\log_4 x-3x\log_2 3-5\log_4 x+10\log_2 3 =\log_4\left(\frac{x^{6x-5}}{3^{6x-20}}\right).6xlog4x−3xlog23−5log4x+10log23=log4(36x−20x6x−5).(4)▸ Mark scheme← 1.37: 4PM1/1/June/2019 — Question 81.39: 4PM1/1R/June/2019 — Question 3 →
