Further Pure Mathematics 4PM1 / Surds and Logarithmic Functions / 1.71.7: Solve logarithmic equations4PM1/1/June/2021 — Question 8 · 8 marksMark as done · Save for laterGiven that n\displaystyle nn satisfies the equationlogan=loga3+loga(2n−1),\mathrm{log}_a n=\mathrm{log}_a3+\mathrm{log}_a(2n-1),logan=loga3+loga(2n−1),(a) find the value of n\displaystyle nn.(3)Given thatlogpx=3andlogpy−3logp2=4,\mathrm{log}_p x=3 \qquad \text{and} \qquad \mathrm{log}_p y-3\mathrm{log}_p2=4,logpx=3andlogpy−3logp2=4,(b) (i) express x\displaystyle xx in terms of p\displaystyle pp,(1)(ii) express xy\displaystyle xyxy in terms of p\displaystyle pp.(4)▸ Mark scheme← 1.6: 4PM1/2R/June/2022 — Question 81.8: 4PM1/2/June/2021 — Question 7 →
