Further Pure Mathematics 4PM1 / Surds and Logarithmic Functions / 1.311.31: Past-paper question 34PM1/2/June/2025 — Question 3 · 5 marksMark as done · Save for laterGiven that a+b56−25=9+45c\displaystyle \frac{a+b\sqrt{5}}{6-2\sqrt{5}} = \frac{9+4\sqrt{5}}{c}6−25a+b5=c9+45 where a\displaystyle aa, b\displaystyle bb and c\displaystyle cc are prime numbers, find the value of a\displaystyle aa, the value of b\displaystyle bb and the value of c\displaystyle cc(5)▸ Mark scheme← 1.30: 4PM1/1R/June/2025 — Question 71.32: 4PM1/2/June/2025 — Question 7 →