Target Mathematics

1.46: Relationships between roots

4PM1/1/June/2015 — Question 5 · 9 marks

(a) Show that (α+β)(α2αβ+β2)=α3+β3(\alpha+\beta)(\alpha^2-\alpha\beta+\beta^2)=\alpha^3+\beta^3. (1)
The roots of the equation 2x2+6x7=02x^2+6x-7=0 are α\alpha and β\beta, where α>β\alpha>\beta. Without solving the equation,
(b) find the value of α3+β3\alpha^3+\beta^3. (4)
(c) show that αβ=23\alpha-\beta=\sqrt{23}. (2)
(d) Hence find the exact value of α3β3\alpha^3-\beta^3. (2)