Further Pure Mathematics 4PM1 / The Quadratic Function / 1.201.20: Past-paper question 104PM1/2/November/2023 — Question 10 · 10 marksMark as done · Save for laterThe roots of a quadratic equation are α\displaystyle \alphaα and β\displaystyle \betaβ whereα+β=−52andα3+β3=1158\alpha + \beta = -\frac{5}{2} \quad \mathrm{and} \quad \alpha^3 + \beta^3 = \frac{115}{8}α+β=−25andα3+β3=8115(a) Show that αβ=4\displaystyle \alpha\beta = 4αβ=4(3)(b) Form a quadratic equation with integer coefficients, that has rootsα2+1βandβ2+1α\frac{\alpha^2 + 1}{\beta} \quad \mathrm{and} \quad \frac{\beta^2 + 1}{\alpha}βα2+1andαβ2+1(7)▸ Mark scheme← 1.19: 4PM1/2/November/2023 — Question 11.16: 4PM1/2R/June/2023 — Question 1 →