Further Pure Mathematics 4PM1 / The Quadratic Function / 1.221.22: Past-paper question 104PM1/1R/June/2024 — Question 10 · 12 marksMark as done · Save for laterThe quadratic equation 2x2+kx+4=0\displaystyle 2x^2 + kx + 4 = 02x2+kx+4=0 has roots α\displaystyle \alphaα and β\displaystyle \betaβ such thatk<0andα>βk < 0 \mathrm{and} \alpha > \betak<0andα>βGiven that α2−β2=7174\displaystyle \alpha^2 - \beta^2 = \frac{7\sqrt{17}}{4}α2−β2=4717(a) show that k=−7\displaystyle k = -7k=−7(8)(b) Hence form a quadratic equation that has roots(α−β)and(α+β)(\alpha - \beta) \mathrm{and} (\alpha + \beta)(α−β)and(α+β)(4)▸ Mark scheme← 1.25: 4PM1/1/November/2024 — Question 101.23: 4PM1/2/June/2024 — Question 2 →