Further Pure Mathematics 4PM1 / Trigonometry / 1.251.25: Trigonometric identities4PM1/2R/June/2024 — Question 11 · 12 marksMark as done · Save for later(a) Using a formula on page 2 show that cos2A=2cos2A−1\cos 2A = 2\cos^2 A - 1cos2A=2cos2A−1(2)(b) Hence show that (2cos2A−1)2=cos4A+12(2\cos^2 A - 1)^2 = \frac{\cos 4A + 1}{2}(2cos2A−1)2=2cos4A+1(3)The curve with equation y=sin2x2+(2cos2x−1)22+18y = \frac{\sin 2x}{2} + \frac{(2\cos^2 x - 1)^2}{2} + \frac{1}{8}y=2sin2x+2(2cos2x−1)2+81 has a stationary point PPP in the range 0≤x≤π60 \leq x \leq \frac{\pi}{6}0≤x≤6π(c) Find the exact coordinates of PPP(7)▸ Mark scheme← 1.24: 4PM1/2R/June/2024 — Question 101.26: 4PM1/1/November/2023 — Question 6 →