Further Pure Mathematics 4PM1 / Trigonometry / 1.381.38: Past-paper question 34PM1/1/November/2024 — Question 3 · 5 marksMark as done · Save for laterTriangle ABC\displaystyle ABCABC is such thatAC=10cmAC = 10 \mathrm{cm}AC=10cmBC=7cmBC = 7 \mathrm{cm}BC=7cmangleCAB=25∘\mathrm{angle} CAB = 25^\circangleCAB=25∘Given that angle ABC\displaystyle ABCABC is obtuse,find, in cm to one decimal place, the length of AB\displaystyle ABAB(5)▸ Mark scheme← 1.30: 4PM1/1/June/2024 — Question 11.39: 4PM1/1/November/2024 — Question 4 →