Further Pure Mathematics 4PM1 / Trigonometry / 1.91.9: Trigonometric equations4PM1/2/June/2025 — Question 1 · 5 marksMark as done · Save for laterSolve the equation3tanA=2sinA\sqrt{3} \mathrm{tan} A = 2 \mathrm{sin} A3tanA=2sinAfor 0∘≤A≤360∘0^\circ \leq A \leq 360^\circ0∘≤A≤360∘(5)▸ Mark scheme← 1.4: 4PM1/2/November/2025 — Question 111.10: 4PM1/2/June/2025 — Question 5 →
