1.38: Past-paper question 8

4PM1/2/June/2024 — Question 8 · 10 marks

1.38 diagram 1
Figure 4 shows a solid right triangular prism ABCDEF\displaystyle ABCDEF
The cross section of the prism is an isosceles triangle.
DEC=AFB=90\displaystyle \angle DEC = \angle AFB = 90^\circ
AB=DC=x\displaystyle AB = DC = x cm
AD=BC=FE=y\displaystyle AD = BC = FE = y cm
AF=BF=DE=CE\displaystyle AF = BF = DE = CE
The triangular faces of the prism are vertical and the edges AD\displaystyle AD, BC\displaystyle BC and FE\displaystyle FE are horizontal.
The volume of the prism is 3.6cm3\displaystyle 3.6 \mathrm{cm}^3
The total external surface area of the prism is Scm2\displaystyle S \mathrm{cm}^2
(a) Show that S\displaystyle S satisfies the equation
S=x22+72(2+1)5xS = \frac{x^2}{2} + \frac{72(\sqrt{2} + 1)}{5x}
(4)
Given that x\displaystyle x can vary,
(b) use calculus, to find to 3 significant figures, the value of x\displaystyle x for which S\displaystyle S is a minimum.
Justify that this value of x\displaystyle x gives a minimum value of S\displaystyle S
(4)
(c) Hence find, to 2 significant figures, the minimum value of S\displaystyle S
(2)