Further Pure Mathematics 4PM1 / Differentiation / 1.421.42: Past-paper question 34PM1/2/November/2024 — Question 3 · 5 marksMark as done · Save for laterThe curve C\displaystyle CC has equation y=e3x(2x−1)4\displaystyle y = \mathrm{e}^{3x}(2x-1)^4y=e3x(2x−1)4Using calculus, find the exact value of the gradient of the tangent to C\displaystyle CC when x=1\displaystyle x = 1x=1(5)▸ Mark scheme← 1.38: 4PM1/2/June/2024 — Question 81.43: 4PM1/2/November/2024 — Question 5 →