1.1: Vectors and an area ratio

Figure 4 shows triangle in which
The point lies on such that .
The point is the midpoint of and the point is the midpoint of .
(a) Find, as simplified expressions in terms of and , the vector
(i) ,
(ii) .
(4)
The point lies on such that is a straight line.
(b) Using a vector method, find as a simplified expression in terms of .
(6)
Given that
(c) find the exact value of .
(4)
