1.2: Vector proof in a quadrilateral

4PM1/1R/June/2022 — Question 9 · 10 marks

1.2 diagram 1
Figure 3 shows quadrilateral ABCD\displaystyle ABCD such that
AD=2a+b,BC=13b,BD=4ab.\overrightarrow{AD}=2\mathbf{a}+\mathbf{b}, \qquad \overrightarrow{BC}=\frac{1}{3}\mathbf{b}, \qquad \overrightarrow{BD}=-4\mathbf{a}-\mathbf{b}.
(a) Prove that AB\displaystyle \overrightarrow{AB} is parallel to DC\displaystyle \overrightarrow{DC}.
(4)
The diagonals, AC\displaystyle AC and BD\displaystyle BD, of the quadrilateral intersect at the point Y\displaystyle Y.
(b) Using a vector method, find AY\displaystyle \overrightarrow{AY} as a simplified expression in terms of a\displaystyle \mathbf{a} and b\displaystyle \mathbf{b}.
(6)